Matematika Sekolah Menengah Pertama sederhana kan perpangkatan berikut ini ​

sederhana kan perpangkatan berikut ini ​

semoga bermanfaat........

Penjelasan dengan langkah-langkah:

Nomor F

[tex] = \frac{ {5}^{5} }{ {5}^{2} \times {5}^{3} } [/tex]

[tex] = {5}^{5 - (2 + 3)} [/tex]

[tex] = {5}^{5 - 5} [/tex]

[tex] = {5}^{0} [/tex]

[tex] = 1[/tex]

[tex] \: [/tex]

Nomor G

[tex] = \frac{ {2}^{7} \times {6}^{7} }{ {4}^{7} } [/tex]

[tex] = \frac{ {2}^{7} \times {(2 \times 3)}^{7} }{ {2}^{2.7} } [/tex]

[tex] = \frac{ {2}^{7} \times {2}^{7} \times {3}^{7} }{ {2}^{14} } [/tex]

[tex] = {2}^{7 + 7 - 14} \times {3}^{7} [/tex]

[tex] = {2}^{0} \times {3}^{7} [/tex]

[tex] = {3}^{7} [/tex]

[tex] \: [/tex]

Nomor H

[tex] = \frac{ {6}^{7} \times {3}^{3} }{ {2}^{7} } [/tex]

[tex] = \frac{ {(2 \times 3)}^{7} \times {3}^{3} }{ {2}^{7} } [/tex]

[tex] = \frac{ \cancel{{2}^{7}} \times {3}^{7} \times {3}^{3} }{ \cancel{{2}^{7}} } [/tex]

[tex] = {3}^{7 + 3} [/tex]

[tex] = {3}^{10} [/tex]

[tex] \: [/tex]

Nomor I

[tex] = \frac{ {10}^{6} \times {4}^{2} }{ {25}^{3} \times {8}^{3} } [/tex]

[tex] = \frac{ {(2 \times 5)}^{6} \times {2}^{2.2} }{ {5}^{2.3} \times {2}^{3.3} } [/tex]

[tex] = \frac{ {2}^{6} \times \cancel {5}^{6} \times {2}^{4} }{ \cancel{{5}^{6}} \times {2}^{9} } [/tex]

[tex] = {2}^{6 + 4 - 9} [/tex]

[tex] = {2}^{1} [/tex]

[tex] = 2[/tex]

[tex] \: [/tex]

Nomor J

[tex] = \frac{ {21}^{5} }{ {9}^{2} } \div {( \frac{7}{2} )}^{2} [/tex]

[tex] = \frac{ {(3 \times 7)}^{5} }{ {3}^{2.2} } \div \frac{ {7}^{2} }{ {2}^{2} } [/tex]

[tex] = \frac{ {3}^{5} \times {7}^{5} }{ {3}^{4} } \div \frac{ {7}^{2} }{ {2}^{2} } [/tex]

[tex] = \frac{ {3}^{5} \times {7}^{5} }{ {3}^{4} } \times \frac{ {2}^{2} }{ {7}^{2} } [/tex]

[tex] = {3}^{5 - 4} \times {7}^{5 - 2} \times {2}^{2} [/tex]

[tex] = {3}^{1} \times {7}^{3} \times {2}^{2} [/tex]

[tex] = {2}^{2} \times {3} \times {7}^{3} [/tex]

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